Hello All,
Actually , I tried list out specific days files with for loop in linux terminal .
Please find the below example & details :
Example :
2020
old year ex 2020 & days need to list out files from Feb 26 to Mar 6 2020
-rw-r--r--. 1 weblogic weblogic 0 Feb 26 2020 testing-1490.xls
-rw-r--r--. 1 weblogic weblogic 0 Feb 27 2020 testing-1489.xls
-rw-r--r--. 1 weblogic weblogic 0 Feb 28 2020 testing-1488.xls
-rw-r--r--. 1 weblogic weblogic 0 Feb 29 2020 testing-1487.xls
-rw-r--r--. 1 weblogic weblogic 0 Mar 1 2020 testing-1486.xls
-rw-r--r--. 1 weblogic weblogic 0 Mar 2 2020 testing-1485.xls
-rw-r--r--. 1 weblogic weblogic 0 Mar 3 2020 testing-1484.xls
-rw-r--r--. 1 weblogic weblogic 0 Mar 4 2020 testing-1483.xls
-rw-r--r--. 1 weblogic weblogic 0 Mar 5 2020 testing-1482.xls
-rw-r--r--. 1 weblogic weblogic 0 Mar 6 2020 testing-1481.xls
current year 2024 :
old year ex 2020 & days need to list out files from Feb 26 to Mar 6 2024
-rw-r--r--. 1 weblogic weblogic 0 Feb 26 2024 testing-1490.xls
-rw-r--r--. 1 weblogic weblogic 0 Feb 27 2024 testing-1489.xls
-rw-r--r--. 1 weblogic weblogic 0 Feb 28 2024 testing-1488.xls
-rw-r--r--. 1 weblogic weblogic 0 Feb 29 2024 testing-1487.xls
-rw-r--r--. 1 weblogic weblogic 0 Mar 1 2024 testing-1486.xls
-rw-r--r--. 1 weblogic weblogic 0 Mar 2 2024 testing-1485.xls
-rw-r--r--. 1 weblogic weblogic 0 Mar 3 2024 testing-1484.xls
-rw-r--r--. 1 weblogic weblogic 0 Mar 4 2024 testing-1483.xls
-rw-r--r--. 1 weblogic weblogic 0 Mar 5 2024 testing-1482.xls
-rw-r--r--. 1 weblogic weblogic 0 Mar 6 2024 testing-1481.xls
Please check help me command list out files some duration days files with for loop command in Linux teminal .
if possible print above mentioned scenario with for loop then please provide me command .
I mentioned above is exame & scenario .
if not poosible with for loop command for above mentioned criteria & if not possible with for loop then any specific alternative command meet above mentioned criteria .
I hope , explained issue clearly . Please check & provide me command if possible .
I am wairing for your valuable reply .
Thank you ,
JEESSHNASREE
Hi @jeesshnasree !
Not sure what do you mean by this part of your post :
Why dont you try using "find" command for the purpose something like this :
find . -type f -newermt "2020-02-26" ! -newermt "2020-03-07" and same for 2024 files.
Here 26th Feb in inclusive whereas the 7th Mar is exclusive.
In this case for loop will be complex wherein you have to apply awk and if as well to list the files as per your scenario.
Refer : https://man7.org/linux/man-pages/man1/find.1.html search with newer
Hi @jeesshnasree !
Not sure what do you mean by this part of your post :
Why dont you try using "find" command for the purpose something like this :
find . -type f -newermt "2020-02-26" ! -newermt "2020-03-07" and same for 2024 files.
Here 26th Feb in inclusive whereas the 7th Mar is exclusive.
In this case for loop will be complex wherein you have to apply awk and if as well to list the files as per your scenario.
Refer : https://man7.org/linux/man-pages/man1/find.1.html search with newer
Thank you @Chetan_Tiwary_ ,
I thought it might be any possibility with for loop meet that activity .
Thank you for your valuable help & command .
Thank you ,
JEESSHNASREE
Red Hat
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