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get all the ip address in Linux

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I am working on a script to get all the network interfaces and ip addresses in Linux.

I know how to use ip command to get the ip address.

$ ip add show
1: lo: <LOOPBACK,UP,LOWER_UP> mtu 65536 qdisc noqueue state UNKNOWN group default qlen 1000
    link/loopback 00:00:00:00:00:00 brd 00:00:00:00:00:00
    inet 127.0.0.1/8 scope host lo
       valid_lft forever preferred_lft forever
2: ens192: <BROADCAST,MULTICAST,UP,LOWER_UP> mtu 1500 qdisc mq state UP group default qlen 1000
    link/ether 00:50:56:81:68:27 brd ff:ff:ff:ff:ff:ff
    inet 10.252.9.61/23 brd 10.252.9.255 scope global noprefixroute ens192
       valid_lft forever preferred_lft forever



but how to show format the output like this: interface name: ip address? 

please give some suggestions. Thanks.

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3 Solutions

Accepted Solutions
tnishiok
Flight Engineer
Flight Engineer
  • 1,227 Views

like this?


[student@workstation ~]$ ip -br a | awk -F' ' '{print$1 ": " $3}'
lo: 127.0.0.1/8
eth0: 172.25.250.9/24
virbr0: 192.168.122.1/24

[student@workstation ~]$ ip -br a | awk -F' ' '{print$1 ": " $3}' | awk '{sub("/.*", "");print $0;}'
lo: 127.0.0.1
eth0: 172.25.250.9
virbr0: 192.168.122.1

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Chetan_Tiwary_
Moderator
Moderator
  • 1,208 Views

Hello @linuxlearning !

Try this :

Chetan_Tiwary__0-1690715461112.png

Chetan_Tiwary__1-1690715490224.png

awk '{print $NF,":" $2}': This uses awk to print the last field (interface name) and the second field (IP address) of each line.
cut -d '/' -f 1: This uses cut to extract only the part before the slash (/) from the IP address (to remove the subnet mask information).
sed 's/:/ : /': This uses sed to add spaces around the colon (:) to format the output as "interface name : IP address".

View solution in original post

tnishiok
Flight Engineer
Flight Engineer
  • 1,199 Views

Hi @linuxlearning,

It's the abbreviation of the 'brief' option. Some of the 'ip' command options have abbreviations like `ip -brief address` ==`ip -br a`.

shell.jpg

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5 Replies
tnishiok
Flight Engineer
Flight Engineer
  • 1,228 Views

like this?


[student@workstation ~]$ ip -br a | awk -F' ' '{print$1 ": " $3}'
lo: 127.0.0.1/8
eth0: 172.25.250.9/24
virbr0: 192.168.122.1/24

[student@workstation ~]$ ip -br a | awk -F' ' '{print$1 ": " $3}' | awk '{sub("/.*", "");print $0;}'
lo: 127.0.0.1
eth0: 172.25.250.9
virbr0: 192.168.122.1

  • 1,209 Views

@tnishiok  Thanks a lot for the help.  It is working as expected. But I couldn't understand -b -r means even I checked the man page.

I got another solution from this article. https://www.howtouselinux.com/post/check-ip-address-in-linux

ip -4 -o a | cut -d ' ' -f 2,7 | cut -d '/' -f 1

lo 127.0.0.1

ens192 10.252.9.61

It is also working.

tnishiok
Flight Engineer
Flight Engineer
  • 1,200 Views

Hi @linuxlearning,

It's the abbreviation of the 'brief' option. Some of the 'ip' command options have abbreviations like `ip -brief address` ==`ip -br a`.

shell.jpg

Chetan_Tiwary_
Moderator
Moderator
  • 1,209 Views

Hello @linuxlearning !

Try this :

Chetan_Tiwary__0-1690715461112.png

Chetan_Tiwary__1-1690715490224.png

awk '{print $NF,":" $2}': This uses awk to print the last field (interface name) and the second field (IP address) of each line.
cut -d '/' -f 1: This uses cut to extract only the part before the slash (/) from the IP address (to remove the subnet mask information).
sed 's/:/ : /': This uses sed to add spaces around the colon (:) to format the output as "interface name : IP address".

shashi01
Moderator
Moderator
  • 933 Views

Hello @linuxlearning 

You can try 

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